python - If else 语句 - 如何跳过 else？

Question

我下面的代码运行良好，但是，如果我选择“1”，代码将运行 if 语句并打印“成功”，但它也会运行 else 语句并退出。如果用户选择 1,2 或 3，如何停止运行 else 语句？

谢谢!

print "\nWelcome to the tool suite.\nWhich tool would you like to use?\n"
print "SPIES - press 1"
print "SPADE - press 2"
print "SPKF - press 3"
print "For information on tools - press i\n"

choice = raw_input("")
if choice == "1":
    execfile("lot.py")
    print ("success")

if choice == "2":
    #execfile("spade.py")
    print ("success")

if choice == "3":
    #execfile("spkf.py")
    print ("success")

if choice == "i":
    print "Google Maps is awesome.\n"
    print "SPADE\n"
    print "SPKF\n\n"

else:
    print "Error, exiting to terminal"
    exit(1)

Answer 1

您需要 elif 结构。

if choice == "1":
    ...
elif choice == "2":
    ...
else: # choice != "1" and choice != "2"
    ...

否则，不同的if 语句将相互断开。我添加了一个空行来强调:

if choice == "1":
    ...

if choice == "2":
    ...
else: # choice != 2
    ...