Python:调用外部函数时出现问题

Question

我是 Python 的初学者，在使用函数时遇到了问题。我正在制作一个程序，其中我有很多参数供用户选择，我需要允许他们确认或拒绝他们的选择。这是代表我的问题的简化代码部分。

我的代码:

def confirm(function):
    while True:
        answer = raw_input('Are you sure? ')
        if answer == 'yes':
            break
        elif answer == 'no':
            return function() # if the user wants to change their name, recall function
        else:
            continue # to reprompt user if the answer is not "yes" or "no"

def your_name():
    while True:
        name = raw_input("What is your name? ")
        if not name:
            continue # to reprompt user if they do not enter anything
        else:
            confirm(your_name)
            print 'Congratulations! You have a name!'
            break
your_name()

运行此程序时，它会打印祝贺字符串的次数与 answer 收到输入的次数相同。
我的输出:

What is your name? BastionAre you sure? noWhat is your name? ArtexAre you sure? noWhat is your name? FalcorAre you sure? yesCongratulations! You have a name!Congratulations! You have a name!Congratulations! You have a name!

My intention is for the congratulatory message to be printed just one time. How can I edit my function(s) in order to achieve this?

What I've tried:
I have attempted all of these, using the exact same input values I used in my output block above.Within the section of confirm(function) that says:

if answer == 'no':
    return function()

我尝试将其更改为:

if answer == 'no':
    function()

在输出中，这将请求 answer raw_input 3 次，并在每次输入后发布祝贺消息。如果我这样写代码:

if answer == 'no':
    print function()

它将打印祝贺响应 3 次并且每次在下面的单独一行上打印None。我正在寻找一种优雅、干净的格式，所以这行不通。

Answer 1

所以你的问题是你正在创建一种无意义的递归函数，你不需要传递要再次调用的函数，因为你已经在函数内部了。我建议如下:

def confirm():
    while True:
        answer = raw_input('Are you sure? ')
        if answer == 'yes':
            return True
        if answer == 'no':
            return False
        else:
            continue # to reprompt user if the answer is not "yes" or "no"

def your_name():
    while True:
        name = raw_input("What is your name? ")
        if not name:
            continue # to reprompt user if they do not enter anything
        elif confirm():
            print 'Congratulations! You have a name!'
            break
your_name()