我有一个元组列表,我在一个简单的 for 循环中循环遍历这些元组,以识别包含某些条件的元组。
mytuplist =
[(1, 'ABC', 'Today is a great day'), (2, 'ABC', 'The sky is blue'),
(3, 'DEF', 'The sea is green'), (4, 'ABC', 'There are clouds in the sky')]
我希望它像这样高效且可读:
for tup in mytuplist:
if tup[1] =='ABC' and tup[2] in ('Today is','The sky'):
print tup
上面的代码不起作用,也没有打印任何东西。
下面的代码有效,但非常冗长。我如何使它像上面那样?
for tup in mytuplist:
if tup[1] =='ABC' and 'Today is' in tup[2] or 'The sky' in tup[2]:
print tup
您应该使用内置的 any()
功能:
mytuplist = [
(1, 'ABC', 'Today is a great day'),
(2, 'ABC', 'The sky is blue'),
(3, 'DEF', 'The sea is green'),
(4, 'ABC', 'There are clouds in the sky')
]
keywords = ['Today is', 'The sky']
for item in mytuplist:
if item[1] == 'ABC' and any(keyword in item[2] for keyword in keywords):
print(item)
打印:
(1, 'ABC', 'Today is a great day')
(2, 'ABC', 'The sky is blue')
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