python - 基于 django 类的 View get_context_data 得到了一个意外的关键字参数

Question

我正在尝试从基于 Django 类的 View 中创建一个 CRUD 应用程序。这是我更新/创建笔记的观点。

class CreateNoteView(CreateView):

    model = Note
    template_name = 'edit_note.html'

    def get_success_url(self):
        return reverse('notes-list')

    def get_context_data(self):

        context = super(CreateNoteView, self).get_context_data(**kwargs)
        context['action'] = reverse('notes-create')
        return context


class UpdateNoteView(UpdateView):

    model = Note
    template_name = 'edit_note.html'

    def get_success_url(self):
        return reverse('notes-list')

    def get_context_data(self, **kwargs):

        context = super(UpdateNoteView, self).get_context_data(**kwargs)
        context['action'] = reverse('notes-edit',
                                    kwargs={'pk':self.get_object().id})
        return context

这是我的模型文件:

# Create your models here.
class Note(models.Model):

    title = models.CharField(max_length=200)
    description = models.TextField()
    pub_date = models.DateField(auto_now_add=True)

我的 urls 文件如下所示:

urlpatterns = patterns('',
       url(r'^create/$',CreateNoteView.as_view(), name='notes-create',),
       url(r'^$', ListNoteView.as_view(), name='notes-list',),    
       url(r'^edit/(?P<pk>\d+)/$', UpdateNoteView.as_view(), name='notes-edit',),                       
)

模板如下:

{% if note.id %}
<h1> Edit Note </h1>
{% else %}
<h1>Add Notes</h1>
{% endif %}

<form action="{{ action }}" method="POST">
  {% csrf_token %}
  <ul>
    {{ form.as_p }}
  </ul>
  <input type="submit" value="Save" />
</form>
<a href="{% url "notes-list" %}">back to list</a>

我收到一个错误，

异常类型:TypeError at/create/

异常值:get_context_data() 得到了一个意外的关键字参数“form”

这是回溯:

File "/home/.virtualenvs/djtalk/local/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
  115.                         response = callback(request, *callback_args, **callback_kwargs)
File "/home/.virtualenvs/djtalk/local/lib/python2.7/site-packages/django/views/generic/base.py" in view
  68.             return self.dispatch(request, *args, **kwargs)
File "/home/.virtualenvs/djtalk/local/lib/python2.7/site-packages/django/views/generic/base.py" in dispatch
  86.         return handler(request, *args, **kwargs)
File "/home/.virtualenvs/djtalk/local/lib/python2.7/site-packages/django/views/generic/edit.py" in get
  195.         return super(BaseCreateView, self).get(request, *args, **kwargs)
File "/home/.virtualenvs/djtalk/local/lib/python2.7/site-packages/django/views/generic/edit.py" in get
  155.         return self.render_to_response(self.get_context_data(form=form))

Exception Type: TypeError at /create/
Exception Value: get_context_data() got an unexpected keyword argument 'form'

Answer 1

更新

def get_context_data(self):

在 CreateNoteView 中:

def get_context_data(self, **kwargs):

---

当您重写方法时(在本例中为:get_context_data)，您应该尽可能确保保持相同的签名:在本例中，get_context_data 是预计会收到 self, **kwargs。

---

关于您的评论:

class NoteMixin(object):

    model = Note
    template_name = 'edit_note.html'

    def get_success_url(self):
        return reverse('notes-list')

     def get_context_data(self, **kwargs):
        context = super(NoteMixin, self).get_context_data(**kwargs)
        context['action'] = self.get_action()
        return context

class UpdateNoteView(NoteMixin, UpdateView):
    def get_action(self):
        return reverse('notes-edit', kwargs={'pk':self.get_object().id})

class CreateNoteView(NoteMixin, CreateView):
    def get_action(self):
        return reverse('notes-create')