在另一个函数中调用菜单函数

Question

我试图在主函数中调用菜单函数并让它提示，直到用户决定退出，但它似乎没有给我响应。我是这个网站编码的新手，如果有什么，请告诉我。帖子格式我可以改进!

清除键盘功能:

void clearKeyboard(void)
{
    int c;
    while ((c = getchar()) != '\n' && c != EOF);
}

调用菜单的函数:

void ContactManagerSystem(void)
{
    int contactchoice;
    int done = 1;
    char yesno, c;
    do {
        clearKeyboard();
        contactchoice = menu();
        switch (contactchoice) {
        case 1:
            printf("<<< Feature 1 is unavailable >>>\n");
            break;
        case 2:
            printf("<<< Feature 2 is unavailable >>>\n");
            break;
        case 3:
            printf("<<< Feature 3 is unavailable >>>\n");
            break;
        case 4:
            printf("<<< Feature 4 is unavailable >>>\n");
            break;
        case 5:
            printf("<<< Feature 5 is unavailable >>>\n");
            break;
        case 6:
            printf("<<< Feature 6 is unavailable >>>\n");
            break;
        case 0:
            printf("Exit the program? (Y)es/(N)o: ");
            scanf("%c%c", &yesno, &c);
            if (yesno == 'Y' || yesno == 'y' && c == '\n') {
                done = 0;
                break;
            }
            else if (yesno == 'N' || yesno == 'n')
                break;
        default:
            break;
        }

    } while (done == 1);
}

菜单功能:

int menu(void)
{
    int done = 1;
    int choice;
    char c;
    do {
        printf("Contact Management System\n");
        printf("-------------------------\n");
        printf("1. Display contacts\n");
        printf("2. Add a contact\n");
        printf("3. Update a contact\n");
        printf("4. Delete a contact\n");
        printf("5. Search contacts by cell phone number\n");
        printf("6. Sort contacts by cell phone numbe\n");
        printf("0. Exit\n\n");
        printf("Select an option:> ");
        int rtn = scanf("%d%c", &choice, &c);

        if (rtn == EOF || rtn == 0 || c != '\n')
            clearKeyboard();
        else if (choice >= 0 && choice <= 6 && c == '\n')
            done = 0;
        else {
            clearKeyboard();
            printf("*** OUT OF RANGE *** <Enter a number between 0 and 6>: ");
            scanf("%d", &choice);
        }
    } while (done == 1);

    return choice;
}

下图是错误的地方，正确的版本应该做案例 1 而不是再次保留提示菜单。

不正确的部分

提前致谢!!!

Answer 1

你的代码有两个问题。

1. menu() 函数返回 int 并且您在 switch case case '1' 中将 int 与 char 匹配: 应该是case 1:

2. 替换下一行

scanf("%c%c", &yesno,&c); 和 scanf("%c%c", &c,&yesno);

希望对你有帮助。