python - 如何在 Python 中按索引从列表中删除 n 个元素？

Question

让我们假设，

g = ['1', '', '2', '', '3', '', '4', '']

我想从 g 中删除所有 ''，我必须从那里获取

g = ['1', '2', '3', '4']

Answer 1

>>> g = ['1', '', '2', '', '3', '', '4', '']
>>> filter(None, g)
['1', '2', '3', '4']

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Help on built-in function filter in module `__builtin__`:filter(...)filter(function or None, sequence) -> list, tuple, or string   Return those items of sequence for which function(item) is true.  If   function is None, return the items that are true.  If sequence is a tuple   or string, return the same type, else return a list.

You can also use a list comprehension if you prefer

>>> [x for x in g if x!=""]
['1', '2', '3', '4']