Python "Rock, Paper, Scissors"验证

Question

我一直在制作一款剪刀石头布游戏，它运行起来就像做梦一样。但是，当我尝试在(显示为 # 的)中添加一些验证时，我的游戏无法运行。我不确定为什么会这样。

我的代码如下:

    from random import randint
    from sys import exit
    computer = randint(1,3)

    r = "r"
    p = "p"
    s = "s"
    print ("The computer has chosen. Your turn")
    player = input ("r is Rock, p is Paper, and s is Scissors. Put your letter in HERE-----> ")

    #from here

    if (player != r or p or s): 
            player = input ("That wasn't r, p, or s. Please try again. r is Rock, p is Paper, and s is Scissors. Put your letter in HERE-----> ")
            if (player != r or p or s) :
                    print ("Can you srsly not understand that " + player + " is not r, p, or s? I give up")
                    exit()


    #to here



    if (computer == 1):
            AI = ("rock")

    if (computer == 2):
            AI = ("paper")

    if (computer == 3):
            AI = ("scissors")

    if (player == r and computer == 1):
            print ("lol draw")
            exit()

    if (player == p and computer == 2):
            print ("lol draw")
            exit()

    if (player == s and computer == 3):
            print ("lol draw")
            exit()

    if (player == r and computer == 3):
            print ("You WIN!!!!!! AI chose " + AI)

    if (player == p and computer == 1):
            print ("You WIN!!!!!! AI chose " + AI)

    if (player == s and computer == 2):
            print ("You WIN!!!!!! AI chose " + AI)

    if (player == s and computer == 1):
            print ("You LOSE!!!!!! AI chose " + AI)

    if (player == r and computer == 2):
            print ("You LOSE!!!!!! AI chose " + AI)

    if (player == p and computer == 3):
            print ("You LOSE!!!!!! AI chose " + AI)

Answer 1

又是or运算符。

player != r or p or s

应该是

player not in (r, p, s)

或类似的。

解释:

A 或 B 的计算结果为 A，如果 A 被认为是真 (truey)。如果 A 被认为是假的(例如 False、0、0.0、[] , ''), A 或 B 的计算结果为 B。

player != r or p or s 与 (player != r) or p or s 相同。现在 (player != r) or p or s 评估为 True 如果 player != r 和 p否则。因为 True 和 p 都是“truey”，所以这两行是等价的:

if player != r or p or s:
if True: