python - 函数列表 Python

Question

我想在 Codecademy 上解决这个问题，但我无法解决。好的，所以我需要做这个，以便它返回列表中某个单词被说的次数。

这是它说要做的:

Write a function that counts how many times the string "fizz" appears in a list.

1.Write a function called fizz_count that takes a list x as input.

2.Create a variable count to hold the ongoing count. Initialize it to zero.

3.for each item in x:, if that item is equal to the string "fizz" then increment the count variable.

4.After the loop, please return the count variable.

For example, fizz_count(["fizz","cat","fizz"]) should return 2.

下面是我写的:

def fizz_count(x):
    count = 0
    for item in x:
        if item == "fizz":
            count = count + 1
            return count

要看这节课，数字是超市的一天 4/13

Answer 1

你太接近了!你只是弄错了缩进。

你有什么:

for item in x:
    if item == 'fizz':
        count = count + 1
        return count # Returns any time we hit "fizz"!

你需要什么:

for item in x:
    if item == 'fizz':
        count += 1  # how we normally write this
return count   # after the loop, at the base indent level of the function