c - 从 C 中的斐波那契数列返回特定数字

Question

我正在编写一个计算斐波那契数列中特定数字的 C 程序，尽管我无法将序列作为数组返回....

我做错了什么？

int fibonacci(int ceiling){  int counter;  int num1 = 1, num2 = 1;  static int fibArray[1000];  for (counter = 1; counter < ceiling; counter+=2)    {      fibArray[counter] = num1;      fibArray[counter+1] = num2;      num2 += num1;      num1 += num2;    }  return &(fibArray);}

我也得到了错误:

fibonacci.c:28: warning: return makes integer from pointer without a cast

?

Answer 1

由于您要返回一个指向数组的指针，因此返回类型应该是 int*。这是示例代码:

int* fibonacci(int ceiling) //Modified return type
{
  int counter;
  int num1 = 1, num2 = 1;
  static int fibArray[1000];
  for (counter = 1; counter < ceiling; counter+=2)
    {
      fibArray[counter] = num1;
      fibArray[counter+1] = num2;
      num2 += num1;
      num1 += num2;
    }
  return (fibArray); //Return the address of the array's starting position
}