python - 按特定顺序测试多个字符串

Question

有没有办法按特定顺序测试多个字符串？像这样:

if str.find(["who", "are", "you"], "who the heck are you") != -1:
    Print("I AM JOE")

Answer 1

逐字测试，检查每个关键字是否包含在前一个关键字之后。

def find_in_order(text, words):
    tokens = text.split()
    start = 0
    for word in words:
        try:
            start = tokens.index(word, start) + 1
        except:
            return False
    return True

测试:

>>> find_in_order("who the hell are you", ["who", "are", "you"])
True
>>> find_in_order("who the hell is you", ["who", "are", "you"])
False
>>> find_in_order("you who the hell are you", ["who", "are", "you"])
True
>>> find_in_order("who bare bayou", ["who", "are", "you"])
False
>>> find_in_order("who are you", ["who", "are", "are", "you"])
False

或者使用不在空格处拆分的变体，因此 who bare byou 将通过:

def find_in_order(text, words):
    start = 0
    for word in words:
        try:
            start = text.index(word, start) + len(word)
        except:
            return False
    return True