java - 使用 POST 方法的 RESTful Java 客户端

Question

我的 Rest 客户端有问题。我的服务

@POST
@Path("/post")
@Consumes("text/plain")
public Response getNumber(String a){
    return Response.status(201).entity("Number is: "+a.toString()).build();
}

我的客户

   try{
        URL url = new URL("http://localhost:8080/RESTform/core/take/post");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Content-Type", "text/plain");
        String input = "123";
        OutputStream os = conn.getOutputStream();
        os.write(input.getBytes());
        os.flush();
        if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
            throw new RuntimeException("Failed : HTTP error code : "
                + conn.getResponseCode());
        }
        BufferedReader br = new BufferedReader(new InputStreamReader(
                (conn.getInputStream())));
        String output;
        System.out.println("Output from Server .... \n");
        while ((output = br.readLine()) != null) {
            System.out.println(output);
        }
        conn.disconnect();
    }
    catch(MalformedURLException e){}
    catch(IOException e){}  

我的路径是:ProjectName/core/take/post在 Eclipse 中的服务器上调试后，我收到一条消息:

输入状态报告，消息方法不允许，描述 所请求的资源不允许指定的 HTTP 方法。汤姆猫8.0.9

请帮助我:(

Answer 1

我仅将 jersey 1.9 版本提供的 jars(全部)包含到我的库中。

这是 REST 服务:

导入 javax.ws.rs.Consumes;
导入 javax.ws.rs.GET；
导入 javax.ws.rs.POST;
导入javax.ws.rs.Path；
导入 javax.ws.rs.Produces；
导入 javax.ws.rs.core.MediaType;
导入 javax.ws.rs.core.Response;
@Path("/你好")

public class HelloWorld {

@POST
@Path("/post")
@Consumes("text/plain")
public Response getNumber(String a){
    return Response.status(201).entity("Number is: "+a.toString()).build();
}
}

这是其余的客户端:import java.io.BufferedReader;
导入java.io.IOException；
导入 java.io.InputStreamReader;
导入 java.io.OutputStream;
导入 java.net.HttpURLConnection;
导入 java.net.MalformedURLException;
导入java.net.URL;

public class Test {
public static void main(String[] args) {

    try {
        URL url = new URL("http://localhost:5050/REST-simple/rest-simple/hello/post");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Content-Type", "text/plain");
        String input = "123";
        OutputStream os = conn.getOutputStream();
        os.write(input.getBytes());
        os.flush();
        if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
            throw new RuntimeException("Failed : HTTP error code : "
                    + conn.getResponseCode());
        }
        BufferedReader br = new BufferedReader(new InputStreamReader(
                (conn.getInputStream())));
        String output;
        System.out.println("Output from Server .... \n");
        while ((output = br.readLine()) != null) {
            System.out.println(output);
        }
        conn.disconnect();
    } catch (MalformedURLException e) {
    } catch (IOException e) {
    }
}}

试试这个你应该得到输出。