gpt4 book ai didi

c - 结构变量打印

转载 作者:太空宇宙 更新时间:2023-11-04 06:35:49 25 4
gpt4 key购买 nike

我正在编写一个遗传算法,但在打印一些结构变量时遇到了问题。我知道代码可以正确读取它们,因为我得到了一个结果,但是当我尝试在屏幕上或文件中打印它们时,结果为零..

这是我正在使用的代码,你能帮帮我吗...??

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

#define POPSIZE 50
#define MAXGENS 1000
#define NVARS 3
#define PXOVER 0.8
#define PMUTATION 0.15
#define B 2
#define TOURNAMENT_SIZE 2
#define TRUE 1
#define FALSE 0

int generation ;
int cur_best;
FILE *galog_tournament;

struct genotype
{
double gene[NVARS];
double fitness;
double upper[NVARS];
double lower[NVARS];
double cfitness;
double rfitness;
};

struct genotype population[POPSIZE+1];
struct genotype newpopulation[POPSIZE+1];


void initialize(void);
double randval(double,double);
void evaluate(void);
void keep_the_best(void);
void elitist(void);
void tournament_selection(void);
void crossover(void);
void random_Xover(int,int);
void swap(double *,double *);
void non_uniform_mutation(void);
void report(void);
double delta2(int,int);


void initialize(void)
{
FILE *infile;
FILE *bounds;
FILE *popu;
int i,j;
double lbound,ubound;

bounds = fopen("bounds.txt","w");
popu = fopen("population.txt","w");


if((infile = fopen("gadata.txt","r"))== NULL)
{
fprintf(galog_tournament,"\n Cannot open input file\n");
exit(1);
}


for(i = 0; i < NVARS; i++)
{
fscanf(infile, "%lf",&lbound);
fscanf(infile, "%lf",&ubound);

printf("%lf %lf\n",lbound,ubound);

for(j = 0; j < NVARS; j++)
{
population[j].fitness = 0;
population[j].rfitness = 0;
population[j].cfitness = 0;
population[j].lower[i] = lbound;
population[j].upper[i] = ubound;

fprintf(bounds,"%lf %lf\n",&population[j].lower[i],&population[j].upper[i]);

population[j].gene[i] = randval(population[j].lower[i],population[j].upper[i]);

fprintf(popu,"%lf\n",population[j].gene[i]);
}

}
fclose(infile);
fclose(bounds);
fclose(popu);
}

伙计们,非常感谢你们的帮助,实际上我尝试调试代码并稍微更改它,以便在屏幕上打印值。不幸的是,我仍然得到零...!!这是代码和我的带有下限和上限的输入文件

void initialize(void)
{
FILE *infile;
FILE *test;
int i,j;
double lbound,ubound;

test = fopen("test.txt","w");



if((infile = fopen("gadata.txt","r"))== NULL)
{
fprintf(galog_tournament,"\n Cannot open input file\n");
exit(1);
}


for(i = 0; i < NVARS; i++)
{
fscanf(infile, "%lf",&lbound);
fscanf(infile, "%lf",&ubound);

printf("%lf %lf\n",lbound,ubound);


for (j=0; j < POPSIZE; j++) {
population[j].fitness = 0;
population[j].rfitness = 0;
population[j].cfitness = 0;
population[j].lower[i] = lbound;
population[j].upper[i] = ubound;
population[j].gene[i] = randval(population[j].lower[i],
population[j].upper[i]);






}


}

fclose(infile);
fclose(test);

}






0.000000 0.000000
0.000514 0.010514
0.011307 0.021307
0.021876 0.031876
0.033994 0.043994
0.043272 0.053272
0.050229 0.060229
0.053976 0.063976
0.053803 0.063803
0.046640 0.056640
0.029907 0.039907
0.017619 0.027619
0.002316 0.012316
-0.005428 0.004572
-0.00683 0.00317
-0.009743 0.000257
-0.10582 -0.09582
-0.026304 -0.016304
-0.027064 -0.017064
-0.025243 -0.015243
-0.022386 -0.012386
-0.019108 -0.009108
-0.015788 -0.005788
-0.012185 -0.002185
-0.009452 0.000548
-0.052133 0.002867
-0.006128 0.003872
0.000000 0.000000

最佳答案

中删除 &
fprintf(bounds,"%lf  %lf\n",&population[j].lower[i],&population[j].upper[i]);

所以它变成了:

fprintf(bounds,"%lf  %lf\n",population[j].lower[i],population[j].upper[i]);

您想打印变量的值而不是该变量的地址。

将您的编译器设置为显示警告,在这种情况下它会告诉您有关问题。

关于c - 结构变量打印,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15155863/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com