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python noob 在发送谷歌语音文本时遇到问题

转载 作者:太空宇宙 更新时间:2023-11-04 06:35:06 27 4
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我正在编写一个简单的小脚本,以便在 Ultra 音乐节早鸟票开始销售时向我发送短信,以便我抢购。当我开始写这篇文章时,我认为 python 将是实现我目标的快速方法。我所做的是收集链接,然后计算它们并确定是否有变化,然后向几个号码发送谷歌语音短信。这是我针对 stackoverflow 运行的代码。

from googlevoice import Voice
from googlevoice.util import input
from bs4 import BeautifulSoup, SoupStrainer
from time import sleep
import urllib2
from array import *

#define login details
email = 'example@gmail.com'
password = 'password'
url = 'http://stackoverflow.com/questions'

def send_message(var_text):
voice = Voice()
voice.login(email, password)

phoneNumber = array('L',[9998675309, 9998675309])
for i in phoneNumber:
voice.send_sms(i, var_text)

#init
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))

link_count = len(soup)

#start the loop
var = 1
while var == 1 : # This constructs an infinite loop
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
if link_count != len(soup):
string = str('Link Count Changed\n\nSite:\n' + url + '\nPrev:\n' + str(link_count) + '\nNew:\n' + str(len(soup)))
send_message(string)
print (string)
link_count = len(soup)
sleep(10)
pass
else:
print('Number of links ('+ str(link_count) + ') has not changed, going to sleep now.')
sleep(10)
pass
print "Good bye!"

这是我不断收到的错误(似乎只有在发送到多个号码时才会发生)

doesn't work array('L',[9998675309, 9998675309])
works array('L',[9998675309])

错误:

bash-3.2# python gvsendalert.py 
Number of links (195) has not changed, going to sleep now.
Traceback (most recent call last):
File "gvsendalert.py", line 32, in <module>
send_message(string)
File "gvsendalert.py", line 19, in send_message
voice.send_sms(i, var_text)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/voice.py", line 151, in send_sms
self.__validate_special_page('sms', {'phoneNumber': phoneNumber, 'text': text})
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/voice.py", line 225, in __validate_special_page
load_and_validate(self.__do_special_page(page, data))
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/util.py", line 65, in load_and_validate
validate_response(loads(response.read()))
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/util.py", line 59, in validate_response
raise ValidationError('There was a problem with GV: %s' % response)
googlevoice.util.ValidationError: There was a problem with GV: {u'data': {u'code': 58}, u'ok': False}

好的,我已经考虑了你们中的一些人发布的内容并得出了这个结论。对于发送我的谷歌语音号码两次的数字数组,它将发送 2 条消息。如果我把我的 friend 号码放在第二位,它就会崩溃。这可能是因为我的 friend 号码不是谷歌语音号码吗?我已经能够使用 Google Voice 和其他一些 3rd 方 iPhone 应用程序向这个号码发送消息,所以我认为 python 模块会以相同的方式工作。

这是我的第二个修订代码:

def send_message(var_text):
voice = Voice()
voice.login(email, password)

phoneNumber = ['myrealgooglenumber', 'myfriendsactualphonenumber']
for i in phoneNumber:
print( str('sending to: ') + str(i))
voice.send_sms(str(i), str(var_text))
sleep(5)

#init
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))

link_count = len(soup)

#start the loop
var = 1
while var == 1 : # This constructs an infinite loop
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
if link_count != len(soup):
string = ('Link Count Changed\n\nSite:\n{0}\nPrev:\n{1}\nNew:\n{2}').format(url, link_count, len(soup))
send_message(string)
link_count = len(soup)
print (string)
sleep(10)
pass
else:
string = ('Number of links ({0}) has not changed, going to sleep now.').format(str(link_count))
print(string)
sleep(10)
pass
print "Good bye!"

已使用 2 个谷歌语音号码进行测试并且有效。仍然不适用于非谷歌语音号码。

最佳答案

看起来您正在为电话号码使用整数。

电话号码不是真实号码。

尝试使用字符串:

phoneNumber = ['9998675309', '9998675309']

此外,在样式注释上,查看字符串格式:

string = 'Link Count Changed\n\nSite:\n{0}\nPrev:\n{1}\nNew:\n{2}').format(url, link_count, len(soup))

关于python noob 在发送谷歌语音文本时遇到问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12342907/

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