python - 将实例/默认值传递给 ModelFormSet，以便在 View 中使用空表单

Question

如何在 ModelFormSet 中预填充 exclude 字段。下面的 AuthorFormSet 在这里没有使用 instance 参数，只有 queryset。那么我如何强制进入的空表单不具有 NULL/None user 属性。我希望能够将该用户字段设置为 request.user

模型.py

class Author(models.Model):
    user = models.ForeignKey(User, related_name='author')
    # assume some other fields here, but not relevant to the discussion.

表单.py

 class AuthorForm(forms.ModelForm):
     class Meta:
         model = Author

 class BaseAuthorFormSet(BaseModelFormSet):
     """will do some clean() here"""
     pass

 AuthorFormSet = modelformset_factory(Author,\
                                    form=AuthorForm, \
                                    formset=BaseAuthorFormSet, extra=1,\
                                    exclude=('user',)
                                    )

View .py

def my_view(request):
    if request.method == 'POST':
        formset = AuthorFormSet(request.POST)
        if form.is_valid(): 
            form.save() # This will cause problems
                        # for the empty form i added,
                       # since user can't  be null.

编辑

这就是我最终所做的事情。 Wogan 的回答部分正确，我认为它只是缺少对所有表单部分的迭代。

for form in formset.forms: 
    form.instance.user = request.user
formset.save()

Answer 1

您可以排除模型表单中的字段，然后这些字段将从 modelformset_factory 创建的表单集中排除。

class AuthorForm(forms.ModelForm):
    class Meta:
        model = Author
        exclude = ('user',)

在您的 View 中，将 commit=False 传递给表单的 save() 方法，然后手动设置用户字段:

def my_view(request):
    if request.method == 'POST':
        formset = AuthorFormSet(request.POST)
        if formset.is_valid(): 
            for author in formset.save(commit=False):
                author.user = request.user
                author.save()
            formset.save_m2m() # if your model has many to many relationships you need to call this