python - SQLAlchemy Select 语句 - SQL 语法错误

Question

我已经创建了一个表(MySQL 5.1)

from sqlalchemy import *

def get():
    db = create_engine('mysql://user:password@localhost/database')
    db.echo = True
    metadata = MetaData(db)

    feeds = Table('feeds', metadata,
            Column('id', Integer, primary_key=True),
            Column('title', String(100)),
            Column('link', String(255)),
            Column('description', String(255)),
    )

    entries = Table('entries', metadata,
            Column('id', Integer, primary_key=True),
            Column('fid', Integer),
            Column('url', String(255)),
            Column('title', String(255)),
            Column('content', String(5000)),
            Column('date', DateTime),
    )
    feeds.create()
    entries.create()

但是当我尝试查询它时:

from sqlalchemy import *
db = create_engine('mysql://user:password@localhost/database')
metadata = MetaData(db)
feeds = Table('feeds', metadata)
s = feeds.select()
result = db.execute(s)

我在 result = db.execute(s) 行中收到一条错误消息，指示如下:

sqlalchemy.exc.ProgrammingError: (ProgrammingError) (1064, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM feeds' at line 2") 'SELECT  \nFROM feeds' ()

我显然是 SQLAlchemy 的新手，而且我不知道自己做错了什么，尽管我已经在网上搜索了每个教程并将其更改了一百万次。有帮助吗？

Answer 1

我怀疑Table.select()仅用于选择特定列。对于 SELECT *，expression language tutorial改为使用此语法:

from sqlalchemy.sql import select
s = select([feeds])
result = db.execute(s)