c - 仅对数组中的偶数求和

Question

在用户输入十个数字后，我想把能被 2 整除的数字相加。

我能够从用户那里获得输入，但我不确定如何检查哪些数字可以被 2 整除，并仅将这些数字相加。

#include <stdio.h>
#include <ctype.h>

int main(void) {
    int i = 0; 
    int val;
    char ch;
    int numbers[10];

    while(i < 10) {

        val = scanf("%d%c", numbers + i, &ch);  

        if(val != 2 || !isspace(ch)) {
            while((ch = getchar()) != '\n')  // discard the invalid input
                ;  
            printf("Error! Entered number is not an integer.\n");
            printf("Please enter an integer again.\n");
            continue;
        }
        ++i;
    }
    printf("%d\n", numbers[0]);
    printf("%d\n", numbers[1]);
    printf("%d\n", numbers[2]);
    printf("%d\n", numbers[3]);
    printf("%d\n", numbers[4]);
    printf("%d\n", numbers[5]);
    printf("%d\n", numbers[6]);
    printf("%d\n", numbers[7]);
    printf("%d\n", numbers[8]);
    printf("%d\n", numbers[9]);

    return 0;
}

Answer 1

怎么样:

int sum = 0;
for (int i = 0; i <= 9; i++)
{
    if (numbers[i] % 2 == 0)
        sum += numbers[i];
}