c - C语言strtok有一些错误

Question

我的代码有问题，我一直收到编译器错误:

error message : warning: assignment makes pointer from integer without a cast

我的代码很简单:

int i;
int arr1[8], arr2[8];
char test[] = "1|a|b;2|c|d;3|e|f";
char *split1, *split2;

split1 = strtok(test, ";");
for(i = 1; i <= 8; i++){
  arr1[i] = split1;
  split1 = strtok(NULL, ";");
  printf("result=%s\n", arr1[i]);
}

当我修复编译器错误时，我的代码无法打印值，反之亦然!

Answer 1

error message : warning: assignment makes pointer from integer without a cast

您需要包含正确的原型(prototype)，以便编译器了解函数返回的类型(否则它会假设它们返回 int)。

strtok() 的原型(prototype)在<string.h> .

#include <string.h>

    split1=strtok(NULL,";"); // without a prototype
                             // the compiler assumes strtok() returns an int
                             // and complains about assigning the int to a pointer