python - 在文件中打印异常

Question

如何仅打印存在于文件/tmp/exceptions.log 中的异常使用 python 忽略所有调试语句。异常的快照如下所示。

     Traceback (most recent call last):
       File "/usr/site/bank/views.py", line 1695, in importmydata
         o.save()
       File "/usr/site/cl/django/django/db/models/base.py", line 435, in save
         self.save_base(using=using, force_insert=force_insert, force_update=force_update)

     IntegrityError: (1048, "Column 'option_b' cannot be null")
     2011-04-14 11:57:40,895 DEBUG In exception
     2011-04-14 11:57:40,915 DEBUG No resource found
     2011-04-14 11:57:40,926 DEBUG Name
     2011-04-14 11:57:40,915 DEBUG No resource found
     2011-04-14 11:57:40,915 DEBUG No resource found
     2011-04-14 11:57:40,915 DEBUG No resource found
     2011-04-14 11:57:40,915 DEBUG No resource found
     Traceback (most recent call last):
       File "/usr/site/bank/views.py", line 1695, in importmydata
         o.save()
       File "/usr/site/cl/django/django/db/models/base.py", line 435, in save
         self.save_base(using=using, force_insert=force_insert, force_update=force_update)

     IntegrityError: (1048, "Column 'option_b' cannot be null")
     2011-04-14 11:57:40,895 DEBUG In exception
     2011-04-14 11:57:40,915 DEBUG No resource found
     2011-04-14 11:57:40,926 DEBUG Name

Answer 1

最简单的方法是使用 grep with exclusion flag ，例如

grep -v DEBUG /tmp/exceptions.log

这将打印不包含“DEBUG”字符串的行。