python可以将图像文件读取为二进制文件

Question

我需要上传一个图像文件，我按照人们的建议使用 MultipartPostHandler.py。但仍然不起作用。这是我的代码:

params = {"upload", open("12345.jpg", "rb")} // in 'rb'
opener = urllib2.build_opener(MultipartPostHandler)
res = opener.open(url, params)

这是 MultipartPostHander 中的代码:

def multipart_encode(vars, files, boundary = None, buffer = None):
    if boundary is None:
        boundary = mimetools.choose_boundary()
    if buffer is None:
        buffer = ''
    for(key, value) in vars:
        buffer += '--%s\r\n' % boundary
        buffer += 'Content-Disposition: form-data; name="%s"' % key
        buffer += '\r\n\r\n' + value + '\r\n'
    for(key, fd) in files:
        file_size = os.fstat(fd.fileno())[stat.ST_SIZE]
        filename = fd.name.split('/')[-1]
        contenttype = mimetypes.guess_type(filename)[0] or 'application/octet-stream'
        buffer += '--%s\r\n' % boundary
        buffer += 'Content-Disposition: form-data; name="%s"; filename="%s"\r\n' % (key, filename)
        buffer += 'Content-Type: %s\r\n' % contenttype
        # buffer += 'Content-Length: %s\r\n' % file_size
        fd.seek(0)
        buffer += '\r\n' + fd.read() + '\r\n'
    buffer += '--%s--\r\n\r\n' % boundary
    return boundary, buffer
multipart_encode = Callable(multipart_encode)

https_request = http_request

错误出现在:

buffer += '\r\n' + fd.read() + '\r\n'

错误是:

'ascii' codec can't decode byte 0xff in position 2: ordinal not in range(128)

这个问题困扰了我很多，请帮帮我!谢谢。

Answer 1

我已经使用 Doug Hellman 的博客中的 MultiPartForm 类成功地将文件上传到我们的邮件服务器:http://pymotw.com/2/urllib2/index.html#module-urllib2

希望你也能使用它。