php - 使用 PHP 调用 Python 网络服务

Question

Python Web 服务代码:

import web 
from soaplib.wsgi_soap import SimpleWSGISoapApp
from soaplib.service import soapmethod
from soaplib.serializers import primitive as soap_types

urls = ("/hello", "HelloService",
        "/hello.wsdl", "HelloService",
        )
render = web.template.Template("$def with (var)\n$:var")



class SoapService(SimpleWSGISoapApp):
    """Class for webservice """
    @soapmethod(soap_types.String,_returns=soap_types.String)
    def hello(self,message):
        """ Method for webservice"""
        return "Hello world "+message



class HelloService(SoapService):
    """Class for web.py """
    def start_response(self,status, headers):
        web.ctx.status = status
        for header, value in headers:
            web.header(header, value)


    def GET(self):
        response = super(SimpleWSGISoapApp, self).__call__(web.ctx.environ, self.start_response)
        return render("\n".join(response))


    def POST(self):
        response = super(SimpleWSGISoapApp, self).__call__(web.ctx.environ, self.start_response)
        return render("\n".join(response))

app=web.application(urls, globals())

if __name__ == "__main__":
    app.run()

PHP 代码:

<?php

    @ini_set("soap.wsdl_cache_enabled", "0");


    $client = new SoapClient('http://localhost:8080/hello.wsdl');

    echo("<pre>");
    var_dump($client->__getFunctions());
    echo("</pre>");
    $params = array('World');


    try {
        print_r($client->__soapCall('hello', $params));

    } catch (SoapFault $exception) {
        echo $exception;
    }
?>

当我运行我的 php 代码时，它会报告以下信息

SoapFault exception: [helloFault] hello() takes exactly 2 arguments (1 given) in C:\website\cosmetics\src\test02.php:15 Stack trace: #0 C:\website\cosmetics\src\test02.php(15): SoapClient->__soapCall('hello', Array) #1 {main}

如何解决这个问题？谢谢。

Answer 1

不确定 SoapClient 到底是什么，但看起来它需要另一个参数。文档怎么说？