java - 有效比较值

Question

有没有更好、更有效的方法来做到这一点:

我输入 2 个值，然后在列表上检查它们，就好像 current = 3 一样，它会返回 true 来检查 1、2 和 3

注意:这些值(一、二、三)只是我使用的示例的占位符，它们之间没有任何关系，只是它们具有不同的优先级。

enum Foo {
    ONE(1), TWO(2), THREE(3)

    private final int priority;

    public Foo(int priority) {this.priority = priority;}

    public int getPriority() {return priority;}
}

public boolean checker(Foo current, Foo check) {
    if (check == ONE) {
        if (current == ONE || current == TWO
                || current == THREE) {
            return true;
        }
    }
    if (check == TWO) {
        if (current == TWO || current == THREE) {
            return true;
        }
    }
    if (check == THREE) {
        if (current == THREE) {
            return true;
        }
    }
    return false;
}

Answer 1

我会这样实现枚举:

enum Foo {
ONE(1), TWO(2), THREE(3);

private final int priority;

private Foo(int priority) {
    this.priority = priority;
}

public int getPriority() {
    return priority;
}

public boolean check(Foo check) {
    return this.getPriority() >= check.getPriority();

}

}

只需调用:

Foo current = Foo.THREE;
System.out.println(current.check(Foo.TWO));

这样就更加面向对象编程了。