c - 在C中打印出动态分配的内存

Question

我完全是编程的初学者，并且得到了一个关于动态分配内存的作业。预期的输出之一是 printf 语句，其中所有输入的输入(整数)都打印在一行中。我设法在 for 循环中打印了 printf，但这还不够。如何在单个代码行中打印它们？这是代码:

int main()
{ 
    int how_many_integers, count, entered_integers, i, *pSize;

    printf("\nHow many integers are you going to type?\n");
    scanf("%i", &how_many_integers);
    getchar();

    // Allocates memory for the integers.
    pSize = malloc (how_many_integers * sizeof(int));

    // Checks if the integer is 0, and/or reads in all the integers.
    if (how_many_integers == 0)
    {
        printf("No numbers were given.\n");
        exit(0);
    }
    printf("Please enter your integers.\n");
    for (int i = 0; i < how_many_integers; i++)
    {
        scanf("%i", &entered_integers);
        count++;
        pSize[i] = entered_integers;
    }
    for (int i = 0; i < how_many_integers; i++)
    {
        printf("Number: %i\n", *(pSize+i));
    }
    free(pSize);

    printf("Count: %i", count);

    return 0;
}

Answer 1

试试这个:

printf("Numbers:");
for (int i = 0; i < how_many_integers; i++)
{
    printf(" %i", *(pSize+i)); // No \n
}
printf("\n"); // if you want a new line at the end

这应该会产生如下输出

数字:1 2 3 4 5

正如其他人提到的，您的 count 变量从未被初始化。将其初始化为 0。