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c - 如何比较结构中的两个字符串

转载 作者:太空宇宙 更新时间:2023-11-04 06:13:49 26 4
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我有一个学校项目,我需要让用户选择按数字或字母顺序对两个学生进行排序。我已经设法完成了第一个(数字顺序),但我无法理解如何按字母顺序排列它们。

学生的姓名由用户提供,并存储在结构中。当我尝试使用时:

if (strcmp((number_name_surname[0].name), (number_name_surname[1].name) < 0));

我得到错误“bool”类型的参数与“const char*”类型的参数不兼容。

这是结构体

typedef struct
{
int number;
char name[10];
char surname[10];
}num_nom_surname;
num_nom_surname *number_name_surname;

这是字母顺序

if(number_name_surname[0].number > number_name_surname[1].number)
{
for (i = number_of_students - 1; i >= 0; i--)
{
printf("\n Student N%c %5d - ", 167, number_name_surname[i].number);
printf("Name: %s %s", number_name_surname[i].name, number_name_surname[i].surname);
}
}
else
{
for (i = 0; i < number_of_students; i++)
{
printf("\n Student N%c %5d - ", 167, number_name_surname[i].number);
printf("Name: %s %s", number_name_surname[i].name, number_name_surname[i].surname);
}
}

这就是我需要帮助的地方

if (strcmp((number_name_surname[0].name), (number_name_surname[1].name) < 0));
{

}

//编辑//

既然我已经完成了,我还有一个问题。为了按字母顺序打印名字,我需要确保名字不同。示例:

如果第一个名字是:Mark Adele,第二个是:Mark Boy,我如何按顺序打印它们?

代码如下:

if (strcmp((number_name_surname[0].name), (number_name_surname[1].name)) < 0) 
{
for (i = 0; i < number_of_students; i++)
{
printf("\n Student N%c %5d - ", 167, number_name_surname[i].number);
printf("Name: %s %s", number_name_surname[i].name, number_name_surname[i].surname);
}
}
else
{
for (i = number_of_students - 1; i >= 0; i--)
{
printf("\n Student N%c %5d - ", 167, number_name_surname[i].number);
printf("Name: %s %s", number_name_surname[i].name, number_name_surname[i].surname);
}
}
printf("\n Value of strcmp: %d", strcmp((number_name_surname[0].name), (number_name_surname[1].name)));

最佳答案

你的括号没了,你有

if (strcmp((number_name_surname[0].name), (number_name_surname[1].name) < 0))

但你需要;

if (strcmp((number_name_surname[0].name), (number_name_surname[1].name)) < 0)

关于c - 如何比较结构中的两个字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50454942/

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