当尝试用 Pandas dataframe
的内容覆盖 sqlite 表时,Pandas DROP
表,但在尝试 之前不会重新创建它插入
。
这是一个最小的工作示例:
import sqlite3 as sq
import pandas as pd
import pandas.io.sql as pd_sql
d = pd.DataFrame({'year':[2008,2008,2008,2008,2009,2009,2009,2009],
'flavour':['strawberry','strawberry','banana','banana',
'strawberry','strawberry','banana','banana'],
'day':['sat','sun','sat','sun','sat','sun','sat','sun'],
'sales':[10,12,22,23,11,13,23,24]})
# Connect to the database (create if necessary)
conn = sq.connect('mydb')
# Create the table 'mytable' if necessary
if not pd_sql.table_exists('mytable', conn, 'sqlite'):
pd_sql.write_frame(d, 'mytable', conn)
# Change some data
d['sales'][d.sales==24] = 25
# Confirm the table exists
print "Table 'mytable' exists:"
print pd_sql.table_exists('mytable', conn, 'sqlite')
# Get some data from the table
cur = pd_sql.execute("SELECT DISTINCT flavour FROM mytable", conn)
print "Here's the data to prove the table exists:"
print cur.fetchall()
try:
print "Attempting write_frame..."
pd_sql.write_frame(d, 'mytable', conn, if_exists='replace')
except sq.OperationalError as e:
print "sq.OperationalError is: " + str(e)
print pd_sql.table_exists('mytable', conn, 'sqlite')
conn.close()
运行此脚本会产生以下输出:
Table 'mytable' exists:
True
Here's the data to prove the table exists:
[(u'banana',), (u'strawberry',)]
Attempting write_frame...
sq.OperationalError is: no such table: mytable
Table 'mytable' exists after write_frame:
False
这看起来像是 Pandas 中的一个错误。有谁能证实这一点?
一如既往的感谢,罗布
在原贴的评论中,已确认这是 Pandas 中的一个已知错误。
这个解决方法对我来说似乎没问题:
pd_sql.uquery("DELETE FROM mytable", conn)
pd_sql.write_frame(d, 'mytable', conn, if_exists='append')
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