python - 当 turtle 到达某个点时停止 turtle ，Python

Question

我目前正在上初级编程课，正在完成作业。现在，我必须用模块 turtle build 3 个房子(我完成了):

def drawBody(mover):
    #Rectangle part
    mover.fillcolor("blue")
    mover.begin_fill()
    for i in range(2):
        mover.forward(100)
        mover.right(90)
        mover.forward(75)
        mover.right(90)
    mover.end_fill()


    #Triangle part
    mover.fillcolor("red")
    mover.begin_fill()
    mover.left(45)
    for i in range(2):
        mover.forward(70.5)
        mover.right(90)
    mover.right(45)
    mover.forward(100)
    mover.end_fill()







#Create preproduction turtle
import turtle
wn = turtle.Screen()
josh = turtle.Turtle()


pointGoTo = -175
for houses in range(3):
    josh.penup()
    josh.goto(pointGoTo,0)
    josh.pendown()

    drawBody(josh)


    josh.right(180)
    pointGoTo = pointGoTo + 125

wn.exitonclick()

这是 while 代码。所以我想让 turtle 停在某个点，红色方 block 的左上角。我已经尝试了多个点，但只是没有中断/停止。我的语法关闭了吗？还是我处理整条房子的事情都错了？如果我含糊不清，请问你有什么不明白的，我真的很想弄清楚，但我完全没有想法。:

def drawBody(mover):
    #Rectangle part
    mover.fillcolor("blue")
    mover.begin_fill()
    for i in range(2):
        mover.forward(100)
        mover.right(90)
        mover.forward(75)
        mover.right(90)
    mover.end_fill()


    #Triangle part
    mover.fillcolor("red")
    mover.begin_fill()
    mover.left(45)
    for i in range(2):
        mover.forward(70.5)
        mover.right(90)
    mover.right(45)
    mover.forward(100)
    mover.end_fill()

    mover.left(90)
    mover.forward(75)
    mover.left(90)
    n = mover.position()
    print(n)
    while True:
        mover.forward(100)
        n = mover.position()
        print(n)
        mover.left(90)
        mover.forward(5)
        mover.left(90)
        n = mover.position()
        print(n)
        mover.forward(100)
        mover.right(90)
        mover.forward(5)
        mover.right(90)


        if n == (-75.30,0.00):
            break







#Create preproduction turtle
import turtle
wn = turtle.Screen()
josh = turtle.Turtle()


pointGoTo = -175
for houses in range(3):
    josh.penup()
    josh.goto(pointGoTo,0)
    josh.pendown()

    drawBody(josh)


    josh.right(180)
    pointGoTo = pointGoTo + 125

wn.exitonclick()

Answer 1

首先，你检查错了地方，你必须在这里检查:

while True:
    mover.forward(100)

    mover.left(90)
    mover.forward(5)
    mover.left(90)
    n = mover.position()

    if abs(n - (-75.30, 0.00)) < 0.01:
        break

    mover.forward(100)
    mover.right(90)
    mover.forward(5)
    mover.right(90)

您的检查不成功，因为 n 实际上是 turtle.Vec2D ，并且坐标是 float ，你可以通过print n[0], n[1]看到。 SO 上有很多关于比较 float 的链接，比如 Testing floating point equality ， 例如。在您的情况下，您可以:

if abs(n - (-75.30, 0.00)) < 0.01:
    break

但我认为，对您来说最好的方法是只绘制固定次数:

mover.left(90)
mover.forward(70)
mover.left(90)
for i in xrange(7):
    mover.forward(100)
    mover.left(90)
    mover.forward(5)
    mover.left(90)

    mover.forward(100)
    mover.right(90)
    mover.forward(5)
    mover.right(90)

您还必须像这样更改您的代码:

for houses in range(3):
    josh.penup()
    josh.goto(pointGoTo,0)
    josh.pendown()

    drawBody(josh)

    pointGoTo = pointGoTo + 125