c - 打印链表中链接的值

Question

我用 C 编写了一个链表程序。但是我打印链表的代码显示错误。我不明白出了什么问题。谁能帮我找出我的代码出了什么问题

#include<stdio.h>
#include<stdlib.h>
struct node{
  int link_data;
  struct node *next;
};
void add_node(struct node *,int);
int delete_node(struct node *);
struct node *front = NULL,*rear = NULL;
int main(){
  struct node *l = (struct node *)malloc(sizeof(struct node *));
  struct node *inc = (struct node *)malloc(sizeof(struct node *));
  int number,i,option,del_node;
  while(1){
    printf("Enter the option:\n1. Add node\n2. Delete node\n");
    scanf("%d",&option);
    switch(option){
      case 1:
        printf("Enter the number to be add\n");
        scanf("%d",&number);
        add_node(l,number);
        break;
      case 2:
        del_node = delete_node(l);
        printf("%d has been removed\n",del_node);
        break;
      case 3:
        for(inc = front ; inc < rear ; inc = inc->next){
          print("%d",inc->link_data);   <<<<<<<<<<<<<<<<< Error part of the program
        }
        break;
      case 4: 
        exit(0);
        break;
    }
  }
}
void add_node(struct node *l,int number){
  struct node *newnode = (struct node *)malloc(sizeof(struct node *));
  if(front == NULL){
    newnode->link_data = number;
    newnode->next = NULL;
    front = newnode;
    l = newnode;    
  }
  else{
    newnode->link_data = number;
    l -> next = newnode;
    l = newnode;
  }
}
int delete_node(struct node *l){
  int node_del;
  struct node *inc;
  for(inc = front ; inc < l ;inc = inc -> next );
  node_del = inc->link_data;
  l = inc;
  l -> next = NULL;
  return node_del; 
}

Answer 1

$ gcc -o ll -Wall -g -O0 ll.c
ll.c: In function ‘main’:
ll.c:29:11: warning: implicit declaration of function ‘print’ [-Wimplicit-function-declaration]
ll.c:13:14: warning: unused variable ‘i’ [-Wunused-variable]

您想使用 printf , 不是 print .还有一个名为 i 的变量你不用的。

在实际的打印位上，您永远不会分配 rear .您可能也不想使用测试 inc < rear ;通常链表在它们的 next 结束时结束指针是 NULL .

在add_node ，你点front到新节点。你可能不是故意的。