c - 函数外释放内存

Question

这是正确的吗，它会在 C 中泄漏内存吗？

unsigned char * prep( int length,int args, ... )
{
    unsigned char *message = (unsigned char *) malloc(length );

    va_list listp;
    va_start( listp, args );

    int i = 0;
    int len = 0;
    unsigned char *source_message ; 
    int step = 0;
    for( i = 0 ; i < args; i++ )
    {

    source_message = va_arg( listp, unsigned char *);
    len = va_arg( listp, long);
    memcpy(message+step, source_message, (long) len);
    step+=len;

    } 
    va_end( listp );
 return message;
}

比调用它并释放外面的指针

unsigned char *mess = prepare_packet_to_send(some vars here);
free(*mess);

Answer 1

没错，它会泄漏内存。不过，只要您记得释放该函数的返回值，就没问题。