c - 使用循环查找除数

Question

我为以下程序编写了代码，但我不明白如何涉及一个函数。这个问题要求我使用一个返回除数之和的函数。请查看问题和我的代码，并尝试帮助我。

问题:

Write a C program that finds and prints the sum of divisors for all the numbers between 101 and 110. The divisors of x are those numbers x divides without a remainder (e.g. the divisors of number 10 are 1, 2, 5, and 10 and their sum = 1+2+5+10=18, the divisors of number 11 are 1 and 11 and their sum=1+11=12, and so forth). Your program should also print the number (101 to 110) that has the maximum sum of divisors.

Your program should use at least one function called div_sum that takes a number and returns its sum of divisors.

我的代码:

#include <iostream>
#include <stdio.h>


int main()

{
int i=1, x=101, sum, smax=0, xmax=0;

    for (x=101; x<=110; x++)
        {  sum=0;

           for(i=1; i<=x; i++)
               {
                  if(x%i==0)
                  sum+=i;
               }

           if(sum>smax)
               {
                  smax=sum;
                  xmax=x;
               }

           printf("The sum of factors of %d = %d\n",x,sum);

        }

    printf("The number that has the maximum sum of divisors is %d with the sum of %d",xmax,smax);

    return 0;
}

Answer 1

您可以将计算每个 x 的除数之和的循环移动到 separate 函数:

int div_sum(int x) {
    int sum = 0;
    for(int i=1; i<=x; i++)
    {
        if(x%i==0)
        sum+=i;
    }
    return sum;
}

并在你的程序中使用它:

for (x=101; x<=110; x++)
{  
   sum= div_sum(x);
   if(sum > amax)
   ...
}