c - 如何在 C 中将 char 分配给 char*？

Question

此代码无效。

char* randomWordHidden[length];
char try;

printf("Enter a letter: ");
scanf(" %c", &try);

//here there is a loop    
  randomWordHidden[i] = try; //assign position of randomWordHidden with try value

它给出错误:[Warning] assignment makes pointer from integer without a cast

但我这样做了并且有效:

randomWordHidden[i] = "H";

如何将 try var 的值分配给 randomWordHidden 的位置？

Answer 1

嗯；

您已经创建了一个指向字符的指针列表(长度为length)。我想你想要的是:

char randomWordHidden[length];

应该是 length 个字符。