python - 在 Python 中使用 Selenium 抓取无限滚动网站

Question

我想删除这个网站有滚动条的内容: http://stocktwits.com/symbol/AAPL?q=AAPL

我在 Stactoverflow 中找到了一个类似问题的答案: scrape websites with infinite scrolling

这是从那里复制的代码:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import NoAlertPresentException
import sys

import unittest, time, re

class Sel(unittest.TestCase):
    def setUp(self):
        self.driver = webdriver.Firefox()
        self.driver.implicitly_wait(30)
        self.base_url = "https://twitter.com"
        self.verificationErrors = []
        self.accept_next_alert = True
    def test_sel(self):
        driver = self.driver
        delay = 3
        driver.get(self.base_url + "/search?q=stckoverflow&src=typd")
        driver.find_element_by_link_text("All").click()
        for i in range(1,100):
            self.driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
            time.sleep(4)
        html_source = driver.page_source
        data = html_source.encode('utf-8')


if __name__ == "__main__":
    unittest.main()

现在我想废弃 Stocktwits 网站而不是 twitter(链接在上面)。

我把上面的代码修改成这样:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import NoAlertPresentException
import sys

import unittest, time, re

class Sel(unittest.TestCase):
    def setUp(self):
        self.driver = webdriver.Firefox()
        self.driver.implicitly_wait(30)
        self.base_url = "http://stocktwits.com/symbol/AAPL?q=AAPL"
        self.verificationErrors = []
        self.accept_next_alert = True
    def test_sel(self):
        driver = self.driver
        delay = 3
        driver.get(self.base_url)
        driver.find_element_by_link_text("All").click()
        for i in range(1,100):
            self.driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
            time.sleep(4)
        html_source = driver.page_source
        data = html_source.encode('utf-8')


if __name__ == "__main__":
    unittest.main()

但是当我运行代码时出现这个错误:

NoSuchElementException: Message: Unable to locate element: {"method":"link text","selector":"All"}

我感谢任何帮助找出问题的帮助。

Answer 1

看起来问题出在这一行:

driver.find_element_by_link_text("All").click()

您期待一个带有链接文本 "All" 的元素，但不存在。