python - 在没有 collections.counter 的情况下根据整数值对字典进行排序

Question

我正在尝试根据元组的第二个值对字典进行排序，例如下面的字典(word_list)可能会给我:

{'accumulative': 2, 'vacuum': 3, 'moonless': 1, 'castle': 4, 'professing': 1, 'poetry': 6}

我不确定如何正确地从最高到最低对字典进行排序(首先出现的是诗歌，最后出现的是 moonless。

def dictionary(word_list):
    freq_dic = {}
    for word in word_list:
        try: 
            freq_dic[word] += 1
        except: 
            freq_dic[word] = 1
    return print(freq_dic)

dictionary(word_list)

def sort_key (dictionary(word_list)):
    return dictionary(word_list))[1]

mylist = list(dictionary(word_list).items())

sortedlist = sorted(dictionary(word_list), key = (sort_key),reverse=True)

Answer 1

您可以将其转换为元组，然后从那里继续。

from operator import itemgetter

diction = {'accumulative': 2, 'vacuum': 3, 'moonless': 1, 'castle': 4, 'professing': 1, 'poetry': 6}
print(sorted(diction.items(), key = itemgetter(1), reverse=True))

输出:

[('poetry', 6), ('castle', 4), ('vacuum', 3), ('accumulative', 2), ('moonless', 1), ('professing', 1)]