python - 如何获取执行当前线程的文件的当前路径？

Question

在 python 中，我可以这样做来获取当前文件的路径:

os.path.dirname(os.path.abspath(__file__))

但是如果我在一个线程上运行它说:

def do_stuff():
   class RunThread(threading.Thread):
       def run(self):
           print os.path.dirname(os.path.abspath(__file__))
   a = RunThread()
   a.start()

我收到这个错误:

Traceback (most recent call last):
  File "/usr/lib/python2.7/threading.py", line 551, in __bootstrap_inner
    self.run()
  File "readrss.py", line 137, in run
    print os.path.dirname(os.path.abspath(__file__))
NameError: global name '__file__' is not defined

Answer 1

import inspect
print(inspect.stack()[0][1])

inspect