python - 如何让闪烁的字符串也改变值？ ( python 3.5)

Question

我在 Python 3.5 中有以下代码:

def blink(char):                       
    while 1:                               
        print (char, end = '\r')           
        time.sleep(0.5)                       
        print (' ' * 50, end = '\r')       
        time.sleep(0.5)        

I am using this function to make any string blink for a specific time

问题是，当我在下面的代码中使用它时，它没有达到预期的效果:

while True:
    time.sleep(0.5)
    seconds += 1
    if seconds == 60:
        minutes += 1
        seconds = 0
    if minutes == 60:
        hours += 1
        minutes = 0
    if hours == 24:
        days += 1
        hours = 0
    blink ('Days: %s, Hours: %s, Minutes: %s, Seconds: %s' % (days, hours, minutes, seconds))

I'm using this piece of code to 'simulate' time. The problem is that the output looks like this:

Days: 0, Hours: 0, Minutes: 0, Seconds: 1

This keeps on blinking on the same line as I want it to, but the problem is that the output doesn't increase.

e.g Days: 0, Hours: 0, Minutes: 0, Seconds: 2 etc. 

Answer 1

blink(char) 函数没有结束，所以 while True 循环将卡在它的第一个循环中。

尝试从闪烁函数中移除 while 循环，使其只闪烁一次:

def blink(char):                       
    print(char, end = '\r')           
    time.sleep(0.5)                       
    print(' ' * 50, end = '\r')       
    time.sleep(0.5)

(或者创建一个单独的 blink_once 函数。)