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python - 所有 spritesheet 都显示在屏幕上

转载 作者:太空宇宙 更新时间:2023-11-04 05:41:13 26 4
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我的游戏有问题,这不是错误而是问题。我正在使用 spritesheets 来制作我的游戏并使用 for 循环自动调用我的 Platform 类。但是,当我尝试调用平台类时,它只显示整个 spritesheet。类平台或 level_1 中可能有错误,但我不确定它是什么。如果你有pygame,请你能帮助我吗? An image of what is happening

import pygame
# Colours + Global constants
WHITE = (255, 255, 255)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)
BLACK = (0, 0, 0)
RANDOM = (12, 211, 123)
WIDTH = 800
HEIGHT = 600
SIZE = (WIDTH, HEIGHT)


# CLASSES
# Block is the common platform

平台类:

class Platform(pygame.sprite.Sprite):
def __init__(self, display, x_screen, y_screen, x_sheet, y_sheet, height, length):
super().__init__()

self.image = pygame.image.load("tiles_spritesheet.png")
self.rect = self.image.get_rect()
display.blit(self.image, (x_screen, y_screen), (x_sheet, y_sheet, height, length))

Level_1 类:

class Level01(Level):
def __init__(self, player1, monster, display):
# Initialise level1
super().__init__()
# Level01 things
block = Block(WIDTH*3, 3, BLACK)
Level.all_things = self.all_things

self.sprites.add(player1, monster)
self.platforms.add(block)
self.all_things.add(player1, block, monster)

theLevel = [[1, HEIGHT, 0, 0],
[1, HEIGHT, WIDTH*3, 0]]

level = [[600, 400, 710, 0, 70, 70]]

for platform in theLevel:
block = Block(platform[0], platform[1], RED)
block.rect.x = platform[2]
block.rect.y = platform[3]
self.platforms.add(block)
self.all_things.add(block)

for goodPlatform in level:
platform = Platform(display, goodPlatform[0], goodPlatform[1], goodPlatform[2], goodPlatform[3], goodPlatform[4], goodPlatform[5])
self.platforms.add(platform)
self.all_things.add(platform)

主要内容:

def main():
# Init pygame
pygame.init()
# Set screen
background = pygame.image.load("background.jpg")
backgroundRect = background.get_rect()
display = pygame.display.set_mode(background.get_size())
# Creating FPS thingy
clock = pygame.time.Clock()
# Making levels + Player
monster = Monster(30, 30, RANDOM)
player = Player()
level_1 = Level01(player, monster, display)
# Choosing level
levelList = []
levelList.append(level_1)
currentLevelNumber = 0
currentLevel = levelList[currentLevelNumber]
y_speed = -5
# Game loop
loop = True
while loop == True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_RIGHT:
player.move_right()
if event.key == pygame.K_LEFT:
player.move_left()
if event.key == pygame.K_UP:
player.move_up(currentLevel.platforms)
if event.key == pygame.KMOD_LSHIFT and event.key == pygame.K_RIGHT:
player.sprint()
if event.type == pygame.KEYUP:
if event.key == pygame.K_LEFT and player.sprite_x_change < 0:
player.stop()
if event.key == pygame.K_RIGHT and player.sprite_x_change > 0:
player.stop()
if event.key == pygame.KMOD_LSHIFT:
player.sprite_x_change -= 10
# Update things
#monster.jump()
if player.rect.x > 400:
player.rect.x = 400
currentLevel.scroll_x(-10)

if player.rect.x >= WIDTH:
player.rect.x = WIDTH
currentLevel.scroll(0)

if player.rect.y >= HEIGHT:
main()

if player.sprite_x_change < 0 and player.rect.x >= 120:
currentLevel.scroll_x(0)

if currentLevel.shift_x >= WIDTH *3 - 400:
currentLevel.scroll_x(0)
sprite_x_change = 0

if player.rect.left <= 120 and player.sprite_x_change < 0:
player.rect.x = 120
player.rect.left = 120
currentLevel.scroll_x(10)
'''
if player.rect.y <= 300:
if player.standing == False and player.sprite_y_change < 0:
currentLevel.scroll_y(10)

if currentLevel.shift_y > 0:
y_speed = -4
if player.standing == True and player.rect.y < 300:
y_speed = 4
print(currentLevel.shift_y)
currentLevel.scroll_y(y_speed)
'''
display.blit(background, backgroundRect)
currentLevel.drawer(display)
# Refresh screen
player.updater(currentLevel.platforms)
clock.tick(30)
pygame.display.update()
pygame.quit()
loop = False

if __name__ == "__main__":
main()

最佳答案

Group 使用 self.imageself.rectblit 元素 so

  1. 使用 pygame.Surface.subsurface 创建地下和 (x_sheet, y_sheet, height, length) - 并分配给 self.image

  2. (x_screen, y_screen, height, length) 分配给 self.rect

.

class Platform(pygame.sprite.Sprite):

def __init__(self, display, x_screen, y_screen, x_sheet, y_sheet, height, length):
super().__init__()

self.tiles = pygame.image.load("tiles_spritesheet.png")

self.image = self.tiles.subsurface(pygame.Rect(x_sheet, y_sheet, height, length))
self.rect = self.image.get_rect(x=x_screen, y=y_screen)


#display.blit(self.image, self.rect)

关于python - 所有 spritesheet 都显示在屏幕上,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33833049/

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