python - UpdateView 不会保存表单，按保存后出现 404 错误

Question

正如标题所说，我很难使 UpdateView 正常工作。当我按下保存时，表单没有保存，我收到 404 错误消息，消息没有用户匹配给定的查询。我在尝试完成这项工作时遇到了非常困难的时间，并且花了数小时在线查看示例，但仍然无法弄清楚我哪里出错了!如果您能对此有所启发，我们将不胜感激!

澄清一下，我希望我的用户能够编辑他们的项目，并且只有该用户可以编辑它。我怀疑我可能做错了很多事!

网址

urlpatterns = patterns('',
        url(r'^$', views.index, name='index'),
        url(r'^register_profile/$', views.register_profile, name='register_profile'),
        url(r'^update_profile/$', views.update_profile, name='update_profile'),
        url(r'^create_project/$', login_required(views.CreateProject.as_view()), name='create_project'),
        url(r'^update_project/(?P<username>\w+)/(?P<slug>[-\w]+)/$', login_required(views.UpdateProject.as_view()), name='update_project'),
        url(r'^(?P<username>\w+)/$', views.profile_page, name='user_profile'),
        url(r'^(?P<username>\w+)/(?P<slug>[-\w]+)/$', views.project_page, name='user_project'),
        )

观看次数

class UpdateProject(UpdateView):
    model = UserProject
    form_class = UserProjectForm
    template_name = 'howdidu/update_project.html'

    def get_object(self, *args, **kwargs):
        obj = super(UpdateProject, self).get_object(*args, **kwargs)
        if obj.user != self.request.user:
            raise PermissionDenied() #or Http404
        return obj

    def form_valid(self, form):
        userproject = form.save(commit=False)
        form.instance.user = self.request.user
        userproject.save()
        self.object = userproject
        return super(UpdateProject, self).form_valid(form)

    def get_success_url(self):
        project_username = self.request.user.username
        project_slug = self.object.slug
        return reverse('user_project', kwargs={'username':project_username, 'slug': project_slug})

模型

class UserProject(models.Model):
    user = models.ForeignKey(User)
    title = models.CharField(max_length=100)
    project_overview = models.CharField(max_length=1000)
    project_picture = models.ImageField(upload_to='project_images', blank=True)
    date_created = models.DateTimeField(auto_now_add=True)
    project_views = models.IntegerField(default=0)
    project_likes = models.IntegerField(default=0)
    project_followers = models.IntegerField(default=0)
    slug = models.SlugField(max_length=100, unique=True) #should this be unique or not?

    def save(self, *args, **kwargs):
        self.slug = slugify(self.title)
        super(UserProject, self).save(*args, **kwargs)

    def __unicode__(self):
        return self.title

project.html 模板

{% extends 'howdidu/base.html' %}

{% load staticfiles %}

{% block title %}Project{% endblock %}

{% block body_block %}

        {% if project %}

        <h1>{{ project.title }}</h1>
        <img src="{{ project.project_picture.url }}" width = "300" height = "300"  />
        <h3>{{ project.project_overview }}</h3>
        <p><a href="{% url 'update_project' project_user.username project.slug %}">Edit project</a></p>

        {% else %}
            The specified project {{ project.title }} does not exist!
        {% endif %}

{% endblock %}

update_project.html 模板

{% extends 'howdidu/base.html' %}

{% load staticfiles %}

{% block title %}Update project{% endblock %}

{% block body_block %}

        <h1>Edit your project</h1>

        <form enctype="multipart/form-data" id="UserProjectForm" method="post" action="/update_project/">
          {% csrf_token %}
          {{ form.as_p }}
          <input type="submit" name="submit" value="Save" />
        </form>

{% endblock %}

Answer 1

您的表单操作是 /update_project/，但这与您更新项目的 url 模式不匹配。相反，该 url 匹配 views.profile_page View ，它将 update_project 视为用户名。这会引发 404，因为您没有使用该用户名的用户。

如果删除表单的 action 属性，表单将提交到当前页面，我相信这是您想要的。

或者，您可以将操作更改为

action="{% url 'update_project' project_user.username project.slug %}"

如果这样做，您必须确保变量在模板上下文中。