c - 在 For 循环中一行输出 2 个值 - C

Question

我在函数中有一个 For 循环，如下所示:

int fnSearch(int arnSalaries [10][2], int nSalary, char cFound)
{
    int nRow, nCol;

    printf("Please enter the Salary to find the Employee ID : ");
    scanf("%d", &nSalary);

    for(nRow = 0; nRow < 10; nRow++)
    {
        if(nSalary == arnSalaries[nRow][1])
        {
            printf("\%d found - Employee ID matching that salary is: %d\n", 
                nSalary, arnSalaries[nRow][0]);
            cFound = 'Y';
            //nRow = 10; /* This is to break out of the loop */
        }
    }

    if(cFound == 'N')
    {
        printf("Sorry, that salary does not match an employee\n");
    }

    return cFound;
}

当我输入工资如“10000”时，输出如下:

10000 found - Employee ID matching that salary is: 21
10000 found - Employee ID matching that salary is: 23

我如何更改代码以使其显示如下内容:

10000 found - Employee ID(s) matching that salary is/are: 21, 23

编辑:我不是在寻找要编写的任何代码 - 只是在正确的方向上提示我应该如何解决这个问题

Answer 1

在循环之前打印除 id 号码以外的所有内容。在循环内，只打印 ID 号。循环后，打印一个换行符。