python - 分组所有测试 Python

Question

我有 2 个模块:test1.py 和 test2.py。
test1.py

import unittest

class ArithTest (unittest.TestCase):

    def test_run (self):

        """ Test addition and succeed. """
        self.failUnless (1+1==2, 'one plus one fails!')
        self.failIf (1+1 != 2, 'one plus one fails again!')
        self.failUnlessEqual (1+1, 2, 'more trouble with one plus one!')

if __name__ == '__main__':
    unittest.main()

test2.py

import unittest

class AlgTest (unittest.TestCase):

    def test_alg (self):

        """ Test addition and succeed. """
        self.assertEqual(1+1, 2, '1+1 != 2? whaaat?')
        self.assertEqual(6-5, 1, '6-5 != 5 wft python?')

if __name__ == '__main__':
    unittest.main()

---

-现在-我想创建一个新模块 test3.py 来测试 test1.py 和 test2.py。我现在不知道如何，我在互联网上阅读了有关套装测试的信息，但我不明白。我不想再创建一种调用测试的方法，并在 test3.py 上调用它们。我想将它们分组并调用 test3.py，它们作为 unitests 运行

Answer 1

测试1.py

import unittest

class ArithTest (unittest.TestCase):

    def test_run (self):

        """ Test addition and succeed. """
        self.failUnless (1+1==2, 'one plus one fails!')
        self.failIf (1+1 != 2, 'one plus one fails again!')
        self.failUnlessEqual (1+1, 2, 'more trouble with one plus one!')

    def runTest(self):
        self.test_run()

if __name__ == '__main__':
    unittest.main()

测试2.py

import unittest

class AlgTest (unittest.TestCase):

    def test_alg (self):

        """ Test addition and succeed. """
        self.assertEqual(1+1, 2, '1+1 != 2? whaaat?')
        self.assertEqual(6-5, 1, '6-5 != 5 wft python?')

    def runTest(self):
        self.test_alg()

if __name__ == '__main__':
    unittest.main()

测试3.py

from .test1 import ArithTest
from .test2 import AlgTest
import unittest

def suite_2():
    suite = unittest.TestSuite()
    suite.addTest(ArithTest())
    suite.addTest(AlgTest())

    return suite

if __name__ == '__main__':
    runner = unittest.TextTestRunner()
    test_suite = suite_2()
    runner.run(test_suite)

同时添加一个__init__.py

使用 python3 -m folder_name.test3 运行它