python - python嵌套循环中的列表理解

Question

scrabble_scores = [(1, "EAOINRTLSU"), (2, "DG"), (3, "BCMP"),
               (4, "FHVWY"), (5, "K"), (8, "JX"), (10, "QZ")]
def get_scrabble_scorer():
    print {x:y for x,z in scrabble_scores for y in z}
    pass

get_scrabble_scorer()

我期待一个输出:

[1:'E',1:'A,1:'O',1:'I'....]

这样分数将被映射到单词中的每个字母表但是我得到了输出:

{1: 'U', 2: 'G', 3: 'P', 4: 'Y', 5: 'K', 8: 'X', 10: 'Z'}

帮帮我

Answer 1

您可以将带有打印命令的行更改为:

print [{x:y} for x,z in scrabble_scores for y in z]

那么输出将是:

[{1: 'E'}, {1: 'A'}, {1: 'O'}, {1: 'I'}...