python - 单击启动菜单的按钮后保持菜单打开

Question

我有一个带有菜单的 QToolButton。单击 QToolButton 时，将出现菜单。默认行为是当从菜单中单击一个 Action 时，菜单消失。我怎样才能使菜单保持打开状态，直到用户点击其他地方？

这是显示行为的最小代码:

from PyQt4 import QtGui, QtCore
import sys, os

if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)
    toolButton = QtGui.QToolButton()
    toolButton.setText('Select')
    toolMenu = QtGui.QMenu()
    for i in range(3):
        action = toolMenu.addAction(str(i))
        action.setCheckable(True)
    toolButton.setMenu(toolMenu)
    toolButton.setPopupMode(QtGui.QToolButton.InstantPopup)
    toolButton.show()
    sys.exit(app.exec_())

Answer 1

从 this 无耻地移植这段代码C++ 答案:

from PyQt4 import QtGui, QtCore
import sys, os

if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)
    toolButton = QtGui.QToolButton()
    toolButton.setText('Select')
    toolMenu = QtGui.QMenu()
    for i in range(3):    
        checkBox = QtGui.QCheckBox(str(i), toolMenu)
        checkableAction = QtGui.QWidgetAction(toolMenu)
        checkableAction.setDefaultWidget(checkBox)
        toolMenu.addAction(checkableAction)
    toolButton.setMenu(toolMenu)
    toolButton.setPopupMode(QtGui.QToolButton.InstantPopup)
    toolButton.show()
    sys.exit(app.exec_())