c - 如何在 C 中执行字符串数组的静态初始化

Question

我正在尝试将字符串值分配给 C 中的二维数组。截至目前，我有以下代码，但它不起作用:

char array[9][6];
    array[0][] = "[0x0a]";
    array[1][] = "[0x09]";
    array[2][] = "[0x0b]";
    array[3][] = "[0x08]";
    array[4][] = "[0x0d]";
    array[5][] = "[0x0c]";
    array[6][] = "[0x07]";
    array[7][] = "[0x5c]";
    array[8][] = "[0x22]";

我该怎么做？谢谢

Answer 1

如果您不想静态分配它们，请使用 strcpy() 函数:

#include <strings.h>

int main(int argc, char const* argv[])
{
    char array[9][7];
    strcpy(array[0], "[0x0a]");
    strcpy(array[1], "[0x09]");
    strcpy(array[2], "[0x0b]");
    strcpy(array[3], "[0x08]");
    strcpy(array[4], "[0x0d]");
    strcpy(array[5], "[0x0c]");
    strcpy(array[6], "[0x07]");
    strcpy(array[7], "[0x5c]");
    strcpy(array[8], "[0x22]");

    return 0;
}

静态赋值看起来像这样:

int main(int argc, char const* argv[])
{
    char array[9][7] = {
        "[0x0a]",
        "[0x09]",
        "[0x0b]",
        "[0x08]",
        "[0x0d]",
        "[0x0c]",
        "[0x07]",
        "[0x5c]",
        "[0x22]"
    };

    return 0;
}

(另外，数组的第二个维度应该是 7，而不是 6。)