c - C 中未解析的外部符号

Question

未解析的外部符号错误阻止了我的代码的编译。它特别提到了 main 中调用的两个函数。这些功能是我试图创建的开关的一部分，它仍在 build 中。如果有人对我如何修复错误或改进我的代码有任何建议，请告诉我并提前感谢您。仅供引用-我已经搜索过类似的问题，但它们并不特定于我的问题...

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//This is a macro intended for use with the emplyName array.
#define SIZE 20 

//This struct has all the varibles that I will be using in my functions
typedef struct person
{
    char* emplyName[5][SIZE];
    float emplyHours[5];
    float emplyRate[5];
    float emplyGross[5];
    float emplyBase[5];
    float emplyOvrt[5];
    float emplyTax[5];
    float emplyNet[5];
    float emplyTotal[5];
}input;

void menu(void);
void employeeInfo(input* emply);
void editEmployees(input* emply);
void print(input* emply);

int main(void)
{
    struct person *payroll={""};
    int choice = 0;
    menu();
    scanf_s("%c", &choice);
    switch (choice){
    case '1':
        employeeInfo(payroll);
        break;
    case '2':
        editEmployees(payroll);
        break;
    case '3':
        print(payroll);
        break;
    case '4':
        break;
    default:
        printf("Invalid entry\n");
    }
    system("pause");
}

void employeeInfo(input *emply)
{
    int i=0;
    do {
        printf("Enter employee name.\n");
        scanf_s("%s", &emply->emplyName[i]);
        printf("Enter employee hours.\n");
        scanf_s("%f", &emply->emplyHours[i]);
        printf("Enter Hourly rate.\n");
        scanf_s("%f", &emply->emplyRate[i]);
    } while (++i <= 5);

    void calculations(input *emply);/*Write a method that calculates the gross, base and overtime pay, pass by reference.*/
{
    int i;
    i = 0;
    for (i = 0; i < 5; i++){
        if (emply->emplyHours[i] > 40) {
            emply->emplyOvrt[i] = (emply->emplyHours[i] - 40) * (emply->emplyRate[i] * 1.5);
        }
        emply->emplyGross[i] = (((emply->emplyHours[i])*(emply->emplyRate[i])) + emply->emplyOvrt[i]);
        emply->emplyBase[i] = (emply->emplyGross[i]) - (emply->emplyOvrt[i]);
        emply->emplyTax[i] = ((emply->emplyGross[i])*.2);
        emply->emplyNet[i] = (emply->emplyGross[i]) - (emply->emplyTax[i]);
        emply->emplyTotal[0] += emply->emplyGross[i];
    }


}


void print(input *emply);
{
    int i;
    for (i = 0; i < 5; i++)
    {


        printf("Employee Name:%s\n", emply->emplyName[i]);
        printf("Hours Worked:%.2f\n ", emply->emplyHours[i]);
        printf("Hourly Rate:%.2f\n", emply->emplyRate[i]);
        printf("Gross Pay:%.2f\n", emply->emplyGross[i]);
        printf("Base Pay:%.2f\n", emply->emplyBase[i]);
        printf("Overtime Pay:%.2f\n", emply->emplyOvrt[i]);
        printf("Taxes Paid:%.2f\n", emply->emplyTax[i]);
        printf("Net Pay:%.2f\n", emply->emplyNet[i]);
    }
    printf("Total paid to all employees : %.2f\n", emply->emplyTotal[0]);
}
void editEmployees(input*emply);
{
    char edit;
    int i;
    printf("which employee would you like to edit?\n");
    for (i = 0; i < 5; i++){
        printf("%d.%s", i + 1, emply->emplyName[i]);
    }
    scanf_s("%c", &edit);
    switch (edit){
    case '1':
        printf("Enter employee name.\n");
        scanf_s("%s", &emply->emplyName[0]);
        printf("Enter employee hours.\n");
        scanf_s("%f", &emply->emplyHours[0]);
        printf("Enter Hourly rate.\n");
        scanf_s("%f", &emply->emplyRate[0]);
    }
}



}

void menu(void){
    printf("Main Menu\n");
    printf("1. Add Employee\n");
    printf("2. Edit Employee\n");
    printf("3. Print Employee\n");
    printf("4. Print All EMployees\n");
    printf("0. exit\n");

}

Answer 1

您将 editEmployees() 和 print() 定义为局部于 employeeInfo()。

1. 这对程序的其余部分隐藏了它们。
2. 这不是标准 C。
3. 如果您正确地缩进了代码，您自己很可能会注意到这一点。

calculations() 也是如此。