linux - 如何创建一个 bash 文件，为从文件夹 A move 到文件夹 B 的每个文件创建符号链接(symbolic link) (linux)

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如何创建一个 bash 文件，为从文件夹 A move 到文件夹 B 的每个文件创建符号链接(symbolic link) (linux)。但是，这需要从文件夹 A 中选择 150 个最大的当前文件来完成。

Answer 1

可能可以用一行代码编写，但用简单的 bash 脚本(例如)更容易

#!/bin/bash
FolderA="/some/folder/to/copy/from/"
FolderB="/some/folder/to/copy/to/"
while read -r size file; do
  mv -iv "$file" "$FolderB"
  ln -s "${FolderB}${file##*/}" "$file"
done < <(find "$FolderA" -maxdepth 1 -type f -printf '%s %p\n'| sort -rn | head -n150)

注意 ${file##*/} 会删除最后一个 / 之前的所有内容，每

   ${parameter##word}
          Remove matching prefix pattern.  The word is expanded to produce a pattern just as in  pathname  expansion.   If  the
          pattern  matches  the  beginning of the value of parameter, then the result of the expansion is the expanded value of
          parameter with the shortest matching pattern (the ``#'' case) or the  longest  matching  pattern  (the  ``##''  case)
          deleted.   If parameter is @ or *, the pattern removal operation is applied to each positional parameter in turn, and
          the expansion is the resultant list.  If parameter is an array variable subscripted with @ or *, the pattern  removal
          operation is applied to each member of the array in turn, and the expansion is the resultant list.

此外，仅对 $(command) 中的文件执行 似乎是个好主意，但要处理替换和 while/read works better in general to avoid word-splitting issues like splitting up files with spaces, etc...