c - 警告 : Comparison between pointer and integer and escape characters

Question

1) 我在 https://www.tutorialspoint.com/compile_c_online.php 上测试了我的代码它以某种方式通过显示 1,3,27,23,19 的理想输出来工作，但也给了我错误消息，这很奇怪，因为我的所有函数都没有任何整数。谁能告诉我为什么显示错误的行是错误的？

2)我怀疑这与字符'没有被正确处理有关，但我不知道如何打印出除%%之外的所有特殊字符> 和 \\。有人可以告诉我他们的完整列表吗？

编辑:我意识到实际上我弄错了 2 个转义字符(在 https://www.geeksforgeeks.org/escape-sequences-c/ 上找到了它的正确术语)，既是单引号又是双引号。除了这个列表还有其他的吗？

#include <stdio.h>

int improvedCountWords(const char *str) {

    int size=0;
    int number=0;
    int length=0;
    while (str[size]!='\0'){
        if (str[size]==' ' || str[size]=='.' || str[size]=='\\' || str[size]=='*' || str[size]=='"'){
            if (length>0){
                number+=1;
                length=0;
            }

        }
        else if (str[size]=='-' || str[size]=="'"){
            if (length>0){
                length++;
            }

        }
        else{
            length++;
        }
        size++;
    }
    if (length>0){
        number++;
    }
    return number;
}


int main(){
    char s1[]="Panting heavily, he continues his exercises -- grepping, installing new packages, logging in as root, and writing replacements for two-year-old shell scripts in Python.";

    char s2[]="\" You'll know why Python is better than Perl... when you try to read your code *six* months from now ...\"";
    char s3[]="With Yoda strapped to his back, Luke climbs up one of the many thick vines that grow in the swamp until he reaches the Dagobah statistics lab.";

    int x1=improvedCountWords("Python");        
    int x2=improvedCountWords("Python is AWESOME");
    int x3=improvedCountWords(s3);
    int x4=improvedCountWords(s1);
    int x5=improvedCountWords(s2);


    printf("%d,%d,%d,%d,%d",x1,x2,x3,x4,x5);



    return 0;
}

Answer 1

您的指针是 "'"，int 是 str[size] 中的字符值，在 == 比较中被提升。就在这一行，没处理好；

    else if (str[size]=='-' || str[size]=="'"){

您可能需要像这样将它与 '\'' 进行比较；

    else if (str[size]=='-' || str[size]=='\''){