c# - 我如何将此加密从 C# 转换为 C

Question

这是我使用的 C# 代码:

public void Decrypt(byte[] @in, byte[] @out, int size)
{
    lock (this)
    {
        for (ushort i = 0; i < size; i++)
        {
            if (_server)
            {
                @out[i] = (byte)(@in[i] ^ 0xAB);
                @out[i] = (byte)((@out[i] << 4) | (@out[i] >> 4));
                @out[i] = (byte)(ConquerKeys.Key2[_inCounter >> 8] ^ @out[i]);
                @out[i] = (byte)(ConquerKeys.Key1[_inCounter & 0xFF] ^ @out[i]);
            }
            else
            {
                @out[i] = (byte)(ConquerKeys.Key1[_inCounter & 0xFF] ^ @in[i]);
                @out[i] = (byte)(ConquerKeys.Key2[_inCounter >> 8] ^ @out[i]);
                @out[i] = (byte)((@out[i] << 4) | (@out[i] >> 4));
                @out[i] = (byte)(@out[i] ^ 0xAB);
            }
            _inCounter = (ushort)(_inCounter + 1);
        }
    }
}

这就是我将它转换为在 C 中工作的方式。

char* decrypt(char* in, int size, int server)
{
    char out[size];
    memset(out, 0, size);
    for (int i = 0; i < size; i++)
    {
        if (server == 1)
        {
            out[i] = in[i] ^ 0xAB;
            out[i] = out[i] << 4 | out[i] >> 4;
            out[i] = Key2[incounter >> 8] ^ out[i];
            out[i] = Key1[incounter & 0xFF] ^ in[i];
        }
        else if (server == 0)
        {
            out[i] = Key1[incounter & 0xFF] ^ in[i];
            out[i] = Key2[incounter >> 8] ^ out[i];
            out[i] = out[i] << 4 | out[i] >> 4;
            out[i] = out[i] ^ 0xAB;
        }
        incounter++;
    }
    return out;
}

但是由于某些原因，C 无法工作。

Link for the full C# file

Link for the full C file

Link for the C implementation

Answer 1

有一个翻译错误。

C# 行:

@out[i] = (byte)(ConquerKeys.Key1[_inCounter & 0xFF] ^ @out[i]);

成为:

out[i] = Key1[incounter & 0xFF] ^ in[i];

xor (^) 右边的值来自错误的数组。

此外，您将返回一个堆栈分配的变量，这将导致各种问题。

改变:

char out[size];
memset(out, 0, size);

到:

char *out = (char*)calloc(size, sizeof(char));