c - 如何在c中初始化数组？

Question

我已经编写了这段代码，但在编译时我收到消息“无效表达式”对于下面的语句

unsigned short address[] ={0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};/*array is being   initialized here.no problem uptil here.*/
unsigned short rowHead=3;
unsigned short colHead=0;
unsigned short rowTail =0;
unsigned short colTail =0;
unsigned short foodx;
unsigned short foody;
unsigned short turn=0;
void gameOver()
{
unsigned short i=0;
address[] ={0b10000001,0b01000010,0b00100100,0b00011000,
            0b00011000,0b00100100,0b01000010,0b10000001};
/*this is the line where compiler complaints as invalid expression.*/
while(1)
    {
    PORTD &=~(1<<i);
    PORTB =address[i];
    delay_ms(5);
    PORTD |=1<<i;
    i%8;
    }
}

Answer 1

您只能在同时声明和分配变量时这样做。你以后不能这样做。不过，您可以创建另一个变量并为其赋值:

unsigned short address2[] = { 0b10000001,0b01000010,0b00100100,0b00011000,
                              0b00011000,0b00100100,0b01000010,0b10000001 };
address = address2;

这可能之后会对 sizeof(address) 产生问题；如果您需要，最好只使用另一个变量。