php - 如何在 PHP 中复制 cURL 和 python 的 'requests' 库？

Question

我在 Python 中有以下代码运行良好(可以访问):

import requests
username = 'user'
password = 'pass'   

r = requests.get('https://internalwebsite/list', auth=(username, password))

j = r.json()

我如何用 PHP 编写它？

我尝试过类似的方法，但到目前为止没有成功:

$postvars = "username=user&password=pass";

$url = "https://internalwebsite/list";

curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_POST, 1);                //0 for a get request
curl_setopt($ch,CURLOPT_POSTFIELDS,$postvars);
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT ,3);
curl_setopt($ch,CURLOPT_TIMEOUT, 20);

$response = curl_exec($ch);
print "curl response is:" . $response;
curl_close ($ch);

常规 cURL 命令也能正常工作(有响应):

curl -u 'user:pass' https://internalwebsite/list

谢谢。

Answer 1

我相信您应该使用 CURLOPT_USERPWD，而不是为这个特定用例提交 postvars(基于您对我之前的解决方案的评论)

$url = "https://internalwebsite/list";

curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_USERPWD, "myusername:mypassword");
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT ,3);
curl_setopt($ch,CURLOPT_TIMEOUT, 20);

$response = curl_exec($ch);
print "curl response is:" . $response;
curl_close ($ch);