c - 严重内存冲突: Variables clashing in C

Question

    struct Message
{
    char type;
    double idNum;
    char *Time;
    char *asset;
    bool BS;
    float price1;
    int shares1;
    float price2;
    int shares2;        
};
typedef struct Message Message;
struct Asset
        {
            oBook *OrderBook;
            Trade *TradeBook; //will point to the latest trade
            int QtyTraded;
            float ValueTraded;
            char* Time;
        };
typedef struct Asset Asset;
int main(int argc, char*argv[])
    {
        Message* newMessage;
        Asset* Check;
        //manipulation and initialization of Check, so that it holds proper values.

        newMessage = parser("N,2376,01/02/2011 09:15:01.342,JPASSOCIAT FUTSTK 24FEB2011,B,84.05,2000,0,0",newMessage);
    //  MessageProcess(newMessage,AssetMap);
        printf("LAST TRADE ADDRESS %p LAST TRADE TIME %s\n",Check->TradeBook,Check->Time);
    }
    Message*  parser(char *message,Message* new_Message)
    {
        char a[9][256];
        char* tmp =message;
        bool inQuote=0;
        int counter=0;
        int counter2=0;
        new_Message = (Message*)malloc(sizeof(Message));
        while(*tmp!='\0')
        {
            switch(*tmp)
            {
                case ',': if(!inQuote)
                       {    
                        a[counter][counter2]='\0';
                        counter++;
                        counter2=0;
                        }

                      break;
                case '"':
                    inQuote=!inQuote;
                    break;
                default:
                    a[counter][counter2]=*tmp;
                    counter2++;
                    break;
            }
        tmp++;

        }
            a[counter][counter2]='\0';
            new_Message->type = *a[0];
            new_Message->Time  = &a[2][11];
            new_Message->asset = a[3];
            if(*a[4]=='S')
            new_Message->BS = 0;
            else
            new_Message->BS = 1;
            new_Message->price1=atof(a[5]);
            new_Message->shares1=atol(a[6]);
            new_Message->price2=atof(a[7]);
            new_Message->shares2=atol(a[8]);
            new_Message->idNum = atoi(a[1]);
    return(new_Message);
    }

这里有一个严重的内存冲突，在两个不同范围的变量中。我使用 gdb 进行了调查，似乎 new_Message->Time 的地址等于 Check->Time 的地址。

它们都是不同类型的结构 我正在尝试解决这个问题，因为当解析器更改 new_Message->Time 的值时，它会操纵 Check 的内容->时间

请建议如何解决此问题。我已经失去(花费)了大约 10 个小时并计算解决这个问题，还有大量的头发。

索罕

编辑 添加结构定义

Answer 1

您正在使用堆栈分配对象的地址来初始化 new_Message->Time = &a[2][11];