python - jq + 更新json文件并根据ID号附加名称

Question

我们要根据以下规则编辑json文件

我们需要在 mazda 字符串下生成名称 car0X_hyb.com(而 X 是 ID 号)

我们需要更新 Linux 机器上的 json 文件

示例 - ID=1

那么 json 将是这样

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=4 ，则 json 将为

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=6 ，则 json 将为

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=10 ，则 json 将为

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com",
    "car07_hyb.com",
    "car08_hyb.com",
    "car09_hyb.com",
    "car10_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

Answer 1

您可以使用 range 生成后续数字流，使用它们填充模板字符串，并从结果中创建一个数组，例如:

$ jq -n --argjson ID 5 '.mazda = [ range($ID) | "car\("0\(.+1)"[-2:])_hyb.com" ]'
{
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com"
  ]
}
$ jq -n --argjson ID 10 '.mazda = [ range($ID) | "car\("0\(.+1)"[-2:])_hyb.com" ]'
{
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com",
    "car07_hyb.com",
    "car08_hyb.com",
    "car09_hyb.com",
    "car10_hyb.com"
  ]
}

根据ID字符的最大长度调整前导0和-2。