python - 如果 if 语句为真，则扩展和替换

Question

我有一个元组的列表，我只想做一个简单的嵌套循环，它有一个if语句，如果它是True 它应该替换列表中的现有元组。我已经让它同时写入新元组和旧元组，我无法摆脱旧元组。

 list_byte = [(1, 1, 0, '0x1636'), (1, 1, 1, '0x19'), (1, 1, 2, '0x02'), (1, 1, 3, '0x2F'), (1, 2, 0, '0x1637')]
result = (2, '0x02', 'LEV'), (2, '0x19', 'RD'), (2, '0x1636', 'IMG'),(2, '0x1637', 'IEM')

 t = []
    for x in list_byte:
        print(x)
        for y in result:
            #print(y)
            if y[:2] == x[2:]:
            #print(y[:2],'-')
                t.extend([x+y[1:]])
        t.append(x)

现在如何打印:

(1, 1, 0, '0x1636', '0x1636', 'IGM')
(1, 1, 0, '0x1636')
(1, 1, 1, '0x19', '0x19', 'RD')
(1, 1, 1, '0x19')
(1, 1, 2, '0x02', '0x02', 'LEV')
(1, 1, 2, '0x02')
(1, 1, 3, '0x2F')
(1, 2, 0, '0x1637', '0x1637', 'IEM')
(1, 2, 0, '0x1637')

我尝试使用 else:在 if 之后，但随后循环变得疯狂并以奇怪的序列打印每个值......这就是我得到的壁橱。

我希望它现在如何打印:

(1, 1, 0, '0x1636', '0x1636', 'IGM')
(1, 1, 1, '0x19', '0x19', 'RD')
(1, 1, 2, '0x02', '0x02', 'LEV')
(1, 1, 3, '0x2F')
(1, 2, 0, '0x1637', '0x1637', 'IEM')

Answer 1

经过一些实验后设法让这段代码运行起来。用 Python 3.6 编写。 (如果您使用的是 Python 2.x，只需将 print(i) 替换为 print i。

修改后的代码

list_byte = [(1, 1, 0, '0x1636'), (1, 1, 1, '0x19'), (1, 1, 2, '0x02'), (1, 1, 3, '0x2F'), (1, 2, 0, '0x1637')]
result = (2, '0x02', 'LEV'), (2, '0x19', 'RD'), (2, '0x1636', 'IMG'),(2, '0x1637', 'IEM')

t = []
for x in list_byte:
    line = x
    for y in result:       
        if y[1] == x[3]:
            line = x + y[1:]
    t.append(line)

for i in t: print(i)

控制台输出:

(1, 1, 0, '0x1636', '0x1636', 'IMG')
(1, 1, 1, '0x19', '0x19', 'RD')
(1, 1, 2, '0x02', '0x02', 'LEV')
(1, 1, 3, '0x2F')
(1, 2, 0, '0x1637', '0x1637', 'IEM')