linux - 查找文件中出现的 X 次字符串并替换为静态字符串

Question

我再次需要你的帮助。我需要找到 3 次和 4 次出现的逗号(跨行)并替换为特定字符串，让我们假设:

"Text","Text2","Text3","Text4","Text5"
"Text6","Text7","Text8","Text9","Text10"

现在，我想将 Text4、Text9、Text5、Text10 替换为例如。 “静态”

 "Text","Text2","Text3","Static","Static"
 "Text6","Text7","Text8","Static","Static"

我应该使用哪个函数？知道“sed”可能适合这样做，但是如何计算逗号呢？

编辑:(更简单的版本，仅出现 3 次逗号)

我只需要找到 3 次出现的逗号(跨行)并替换为特定字符串，让我们假设:

"Text","Text2","Text3","Text4","Text5"
"Text6","Text7","Text8","Text9","Text10"

现在，我想将 Text4,Text9 替换为例如。 “静态”

 "Text","Text2","Text3","Static","Text5"
 "Text6","Text7","Text8","Static","Text5"

Answer 1

这个 awk 单行代码适用于给定的示例。它更改第四和第五列/字段中的文本:

awk -F, -v OFS="," '{i=4;while(i<6)gsub(/\w+/,"Static",$(i++))}7' file